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Backpressure

David Gross edited this page Jul 15, 2014 · 40 revisions

Work in progress...

In RxJava it is not difficult to get into a situation in which an Observable is emitting items more rapidly than an operator or subscriber can consume them. This presents the problem of what to do with such a growing backlog of unconsumed items.

For example, imagine using the zip operator to zip together two infinite Observables, one of which emits items twice as frequently as the other. The zip operator, to perform as advertised, will have to maintain an ever-expanding buffer of items emitted by the faster Observable to combine with items emitted by the slower one. This could cause RxJava to seize an unwieldy amount of system resources.

You can tell RxJava how you want it to handle cases like these. RxJava is capable of exerting backpressure on Observables. This page tells you how the backpressure options work, and also how you can design your own Observables and Observable operators to respect backpressure requests.

Useful Operators that Avoid the Need for Backpressure

Your first line of defense against the problems of over-producing Observables is the ordinary set of Observable operators. In particular, operators like sample( ) or throttleLast( ), throttleFirst( ), and throttleWithTimeout( ) or debounce( ) allow you to regulate the rate at which an Observable emits items.

We might, for example, have used one of these operators on each of the two Observables we intended to zip together in the conundrum mentioned earlier, and this would have solved our problem. But the behavior of the resulting zip would also have been different. It would no longer necessarily zip together the nth item from each Observable sequentially.

Backpressure Isn't Magic

Backpressure doesn't make the problem of an overproducing Observable or an underconsuming Subscriber go away. It just moves the problem up the chain of operators to a point where it can be handled better.

Let's take a closer look at the problem of the uneven zip.

You have two Observables, A and B, where B is inclined to emit items more frequently as A. When you try to zip these two Observables together, the zip operator combines item n from A and item n from B, but meanwhile B has also emitted items n+1 to n+m. The zip operator has to hold on to these items so it can combine them with items n+1 to n+m from A as they are emitted, but meanwhile m keeps growing and so the size of the buffer needed to hold on to these items keeps increasing.

You could attach a throttling operator to B, but this would mean ignoring some of the items B emits, which might not be appropriate. What you'd really like to do is to signal to B that it needs to slow down and then let B decide how to do this in a way that maintains the integrity of its emissions.

Backpressure lets you do this. The Subscriber interface has a method called request(_n_) that lets it ask for a specified number of items from the Observable the Subscriber is subscribed to. A Subscriber can call this method inside its onStart() handler to initiate the emission of items and in its onNext() handler to keep the flow of emissions coming. This creates a sort of active pull from the Subscriber in contrast to the normal passive push Observable behavior.

In our zip example, we could tell zip to request one item from both A and B only when zip itself emits an item; that way zip would never have to buffer items from a more prolific Observable.

For this to work, though, A and B (or the Observables that result from operators applied to them) must respond correctly to the request(). If an Observable has not been written to support backpressure, you can apply one of the following operators to it, each of which forces a simple form of backpressure behavior:

onBackpressureBuffer
maintains a buffer of all emissions from the source Observable and emits them to downstream Subscribers according to the requests they generate
onBackpressureDrop
drops emissions from the source Observable unless there is a pending request from a downstream Subscriber, in which case it will emit enough items to fulfill the request

How to request backpressure in a Subscriber

When you subscribe to an Observable with a Subscriber, you can request backpressure by calling Subscriber.request(n) in the Subscriber’s onStart() method, where n is the maximum number of items you want the Observable to emit before the next request() call.

Then, after handling this item (or these items) in onNext(), you can call request() again to instruct the Observable to emit another item (or items). Here is an example of a Subscriber that requests one item at a time from someObservable:

someObservable.subscribe(new Subscriber<t>() {
    @Override
    public void onStart() {
      request(1);
    }

    @Override
    public void onCompleted() {
      // gracefully handle sequence-complete
    }

    @Override
    public void onError(Throwable e) {
      // gracefully handle error
    }

    @Override
    public void onNext(t n) {
      // do something with the emitted item "n"
      // request another item:
      request(1);
    }
});

Work in progress...

Things that may need explaining:

  • the Producer interface (and its request method)
  • other new methods in Subscriber
    • setProducer(p)
    • onSetProducer(p)
  • the new Observable operators:
    • onBackpressureBuffer
    • onBackpressureDrop
  • how and when to support producers in custom observables & operators
    • point here from the "how to make a custom operator" page; maybe also from create operator doc

Work in progress...

See also

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