i386, dumpstack: unify die()

Make i386's die() equal to x86_64's version.

Whitespace-only changes on x86_64, to make it equal to i386's
version. (user_mode and user_mode_vm are equal on x86_64.)

Signed-off-by: Alexander van Heukelum <[email protected]>
Acked-by: Neil Horman <[email protected]>
Signed-off-by: Ingo Molnar <[email protected]>

Author: heukelum

arch/x86/kernel/dumpstack_32.c

@@ -378,15 +378,11 @@ void die(const char *str, struct pt_regs *regs, long err)
 	unsigned long flags = oops_begin();
 	int sig = SIGSEGV;
 
-	if (die_nest_count < 3) {
+	if (!user_mode_vm(regs))
 		report_bug(regs->ip, regs);
 
-		if (__die(str, regs, err))
-			sig = 0;
-	} else {
-		printk(KERN_EMERG "Recursive die() failure, output suppressed\n");
-	}
-
+	if (__die(str, regs, err))
+		sig = 0;
 	oops_end(flags, regs, sig);
 }
 

arch/x86/kernel/dumpstack_64.c

@@ -506,12 +506,16 @@ int __kprobes __die(const char *str, struct pt_regs *regs, long err)
 	return 0;
 }
 
+/*
+ * This is gone through when something in the kernel has done something bad
+ * and is about to be terminated:
+ */
 void die(const char *str, struct pt_regs *regs, long err)
 {
 	unsigned long flags = oops_begin();
 	int sig = SIGSEGV;
 
-	if (!user_mode(regs))
+	if (!user_mode_vm(regs))
 		report_bug(regs->ip, regs);
 
 	if (__die(str, regs, err))