Consider members of public protocol as public symbols

Resolves #12

Author: mattt

Sources/SwiftDoc/Symbol.swift

@@ -41,10 +41,17 @@ public final class Symbol {
             return true
         }
 
-        if declaration is Enumeration.Case,
-            let enumeration = context.compactMap({ ($0 as? Symbol)?.declaration as? Enumeration }).last,
-            enumeration.modifiers.contains(where: { $0.name == "public" }) {
-            return true
+        if let symbol = context.compactMap({ $0 as? Symbol }).first,
+            symbol.declaration.modifiers.contains(where: { $0.name == "public" })
+        {
+            switch symbol.declaration {
+            case is Enumeration:
+                return declaration is Enumeration.Case
+            case is Protocol:
+                return declaration is Function || declaration is Variable
+            default:
+                break
+            }
         }
 
         return false

Tests/SwiftDocTests/SourceFileTests.swift

@@ -29,7 +29,7 @@ final class SourceFileTests: XCTestCase {
         public struct S {}
 
         /// Extension
-        extension S: P {
+        public extension S: P {
             /// Function
             func f() {}
 
@@ -40,10 +40,10 @@ final class SourceFileTests: XCTestCase {
         /// Class
         open class C: P{
             /// Function
-            func f() {}
+            public func f() {}
 
             /// Property
-            var p: Any { return () }
+            public var p: Any { return () }
         }
 
         /// Subclass
@@ -58,6 +58,10 @@ final class SourceFileTests: XCTestCase {
 
         XCTAssertEqual(sourceFile.symbols.count, 12)
 
+        for symbol in sourceFile.symbols {
+            XCTAssert(symbol.isPublic, "\(symbol.declaration) isn't public")
+        }
+
         do {
             let `protocol` = sourceFile.symbols[0]
             XCTAssert(`protocol`.declaration is Protocol)