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| 1 | +/* |
| 2 | +@author : Mayank K Jha |
| 3 | +
|
| 4 | +*/ |
| 5 | + |
| 6 | + |
| 7 | +public class Solution { |
| 8 | + |
| 9 | +public static void main(String[] args) throws IOException { |
| 10 | + Scanner in =new Scanner(System.in); |
| 11 | + |
| 12 | + int n=in.nextInt(); //n = Number of nodes or vertices |
| 13 | + int m=in.nextInt(); //m = Number of Edges |
| 14 | + long w[][]=new long [n+1][n+1]; //Adjacency Matrix |
| 15 | + |
| 16 | + //Initializing Matrix with Certain Maximum Value for path b/w any two vertices |
| 17 | + for (long[] row: w) |
| 18 | + Arrays.fill(row, 1000000l); |
| 19 | + //From above,we Have assumed that,initially path b/w any two Pair of vertices is Infinite such that Infinite = 1000000l |
| 20 | + //For simplicity , We can also take path Value = Long.MAX_VALUE , but i have taken Max Value = 1000000l . |
| 21 | + |
| 22 | + //Taking Input as Edge Location b/w a pair of vertices |
| 23 | + for(int i=0;i<m;i++){ |
| 24 | + int x=in.nextInt(),y=in.nextInt(); |
| 25 | + long cmp=in.nextLong(); |
| 26 | + if(w[x][y]>cmp){ //Comparing previous edge value with current value - Cycle Case |
| 27 | + w[x][y]=cmp; w[y][x]=cmp; |
| 28 | + } |
| 29 | + } |
| 30 | + |
| 31 | + //Implementing Dijkshtra's Algorithm |
| 32 | + |
| 33 | + Stack <Integer> t=new Stack<Integer>(); |
| 34 | + int src=in.nextInt(); |
| 35 | + for(int i=1;i<=n;i++){ |
| 36 | + if(i!=src){t.push(i);}} |
| 37 | + Stack <Integer> p=new Stack<Integer>(); |
| 38 | + p.push(src); |
| 39 | + w[src][src]=0; |
| 40 | + while(!t.isEmpty()){int min=989997979,loc=-1; |
| 41 | + for(int i=0;i<t.size();i++){ |
| 42 | + w[src][t.elementAt(i)]=Math.min(w[src][t.elementAt(i)],w[src][p.peek()] |
| 43 | + +w[p.peek()][t.elementAt(i)]); |
| 44 | + if(w[src][t.elementAt(i)]<=min){ |
| 45 | + min=(int) w[src][t.elementAt(i)];loc=i;} |
| 46 | + } |
| 47 | + p.push(t.elementAt(loc));t.removeElementAt(loc);} |
| 48 | + |
| 49 | + //Printing shortest path from the given source src |
| 50 | + for(int i=1;i<=n;i++){ |
| 51 | + if(i!=src && w[src][i]!=1000000l){System.out.print(w[src][i]+" ");} |
| 52 | + else if(i!=src){System.out.print("-1"+" ");} //Printing -1 if there is no path b/w given pair of edges |
| 53 | + } |
| 54 | + |
| 55 | + } |
| 56 | +} |
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