Look for libllama in parent directory

Author: Don Mahurin

examples/llama_cpp.py

@@ -31,10 +31,12 @@ def _load_shared_library(lib_base_name: str):
 
     # Construct the paths to the possible shared library names
     _base_path = pathlib.Path(__file__).parent.resolve()
+    _base_path_parent = pathlib.Path(__file__).parent.parent.resolve()
     # Searching for the library in the current directory under the name "libllama" (default name
     # for llamacpp) and "llama" (default name for this repo)
     _lib_paths = [
         _base_path / f"lib{lib_base_name}{lib_ext}",
+        _base_path_parent / f"lib{lib_base_name}{lib_ext}",
         _base_path / f"{lib_base_name}{lib_ext}",
     ]