bnxt_en: Refactor TX ring allocation logic

Add a new bnxt_hwrm_tx_ring_alloc() function to handle allocating
a transmit ring.  This will be useful later in the series.

Reviewed-by: Ajit Khaparde <[email protected]>
Reviewed-by: Michal Swiatkowski <[email protected]>
Signed-off-by: Michael Chan <[email protected]>
Link: https://patch.msgid.link/[email protected]
Signed-off-by: Jakub Kicinski <[email protected]>

Author: Michael Chan

drivers/net/ethernet/broadcom/bnxt/bnxt.c

@@ -7218,6 +7218,20 @@ static int bnxt_hwrm_cp_ring_alloc_p5(struct bnxt *bp,
 	return 0;
 }
 
+static int bnxt_hwrm_tx_ring_alloc(struct bnxt *bp,
+				   struct bnxt_tx_ring_info *txr, u32 tx_idx)
+{
+	struct bnxt_ring_struct *ring = &txr->tx_ring_struct;
+	const u32 type = HWRM_RING_ALLOC_TX;
+	int rc;
+
+	rc = hwrm_ring_alloc_send_msg(bp, ring, type, tx_idx);
+	if (rc)
+		return rc;
+	bnxt_set_db(bp, &txr->tx_db, type, tx_idx, ring->fw_ring_id);
+	return 0;
+}
+
 static int bnxt_hwrm_ring_alloc(struct bnxt *bp)
 {
 	bool agg_rings = !!(bp->flags & BNXT_FLAG_AGG_RINGS);
@@ -7254,23 +7268,17 @@ static int bnxt_hwrm_ring_alloc(struct bnxt *bp)
 		}
 	}
 
-	type = HWRM_RING_ALLOC_TX;
 	for (i = 0; i < bp->tx_nr_rings; i++) {
 		struct bnxt_tx_ring_info *txr = &bp->tx_ring[i];
-		struct bnxt_ring_struct *ring;
-		u32 map_idx;
 
 		if (bp->flags & BNXT_FLAG_CHIP_P5_PLUS) {
 			rc = bnxt_hwrm_cp_ring_alloc_p5(bp, txr->tx_cpr);
 			if (rc)
 				goto err_out;
 		}
-		ring = &txr->tx_ring_struct;
-		map_idx = i;
-		rc = hwrm_ring_alloc_send_msg(bp, ring, type, map_idx);
+		rc = bnxt_hwrm_tx_ring_alloc(bp, txr, i);
 		if (rc)
 			goto err_out;
-		bnxt_set_db(bp, &txr->tx_db, type, map_idx, ring->fw_ring_id);
 	}
 
 	for (i = 0; i < bp->rx_nr_rings; i++) {