btrfs: calculate number of eb pages properly in csum_tree_block

Building with -Warray-bounds on systems with 64K pages there's a
warning:

  fs/btrfs/disk-io.c: In function ‘csum_tree_block’:
  fs/btrfs/disk-io.c:226:34: warning: array subscript 1 is above array bounds of ‘struct page *[1]’ [-Warray-bounds]
    226 |   kaddr = page_address(buf->pages[i]);
        |                        ~~~~~~~~~~^~~
  ./include/linux/mm.h:1630:48: note: in definition of macro ‘page_address’
   1630 | #define page_address(page) lowmem_page_address(page)
        |                                                ^~~~
  In file included from fs/btrfs/ctree.h:32,
                   from fs/btrfs/disk-io.c:23:
  fs/btrfs/extent_io.h:98:15: note: while referencing ‘pages’
     98 |  struct page *pages[1];
        |               ^~~~~

The compiler has no way to know that in that case the nodesize is exactly
PAGE_SIZE, so the resulting number of pages will be correct (1).

Let's use num_extent_pages that makes the case nodesize == PAGE_SIZE
explicitly 1.

Reported-by: Gustavo A. R. Silva <[email protected]>
Reviewed-by: Qu Wenruo <[email protected]>
Signed-off-by: David Sterba <[email protected]>

Author: kdave

fs/btrfs/disk-io.c

@@ -209,7 +209,7 @@ void btrfs_set_buffer_lockdep_class(u64 objectid, struct extent_buffer *eb,
 static void csum_tree_block(struct extent_buffer *buf, u8 *result)
 {
 	struct btrfs_fs_info *fs_info = buf->fs_info;
-	const int num_pages = fs_info->nodesize >> PAGE_SHIFT;
+	const int num_pages = num_extent_pages(buf);
 	const int first_page_part = min_t(u32, PAGE_SIZE, fs_info->nodesize);
 	SHASH_DESC_ON_STACK(shash, fs_info->csum_shash);
 	char *kaddr;