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Fortran 2023 subclause 13.7.2.3.8 discusses input rounding only
in the context of decimal-to-binary conversion. There is no
mention of rounding for hexadecimal floating-point input conversion.
At least one Fortran compiler seems to have interpreted this
silence as implying no rounding. (Note that this is not the same
thing as rounding to zero (RZ), which would return +/-HUGE() for
overflow.)
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