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[ET][Portable] Simplify op copy #711
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[ET][Portable] Simplify op copy #711
manuelcandales
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The fact that `src` must broadcast to `in` implies that the result of broadcasting `in` and `src` has shape equal to `in`. Therefore `out` must have the same shape than `in`. Hence, we can avoid calling `get_broadcast_target_size` and simply resize `out` to `in.sizes()` Differential Revision: [D49979519](https://our.internmc.facebook.com/intern/diff/D49979519/) [ghstack-poisoned]
This was referenced Oct 9, 2023
The fact that `src` must broadcast to `in` implies that the result of broadcasting `in` and `src` has shape equal to `in`. Therefore `out` must have the same shape than `in`. Hence, we can avoid calling `get_broadcast_target_size` and simply resize `out` to `in.sizes()` Differential Revision: [D49979519](https://our.internmc.facebook.com/intern/diff/D49979519/) [ghstack-poisoned]
This was referenced Oct 9, 2023
This pull request has been merged in 7a7f9dd. |
This was referenced Oct 10, 2023
Gasoonjia
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Pull Request resolved: pytorch/executorch#711 The fact that `src` must broadcast to `in` implies that the result of broadcasting `in` and `src` has shape equal to `in`. Therefore `out` must have the same shape than `in`. Hence, we can avoid calling `get_broadcast_target_size` and simply resize `out` to `in.sizes()` ghstack-source-id: 203404905 @exported-using-ghexport Differential Revision: [D49979519](https://our.internmc.facebook.com/intern/diff/D49979519/)
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Stack from ghstack (oldest at bottom):
The fact that
src
must broadcast toin
implies that the result of broadcastingin
andsrc
has shape equal toin
. Thereforeout
must have the same shape thanin
. Hence, we can avoid callingget_broadcast_target_size
and simply resizeout
toin.sizes()
Differential Revision: D49979519