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[refs]

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refs/tags/release-0.1: 1f5c5126e96c79d22cb7862f75304136e204f105
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refs/heads/ndm: f3868061cd7988080c30d6d5bf352a5a5fe2460b
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refs/heads/dist-snap: 22efa39382d41b084fde1719df7ae8ce5697d8c9
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refs/tags/release-0.2: c870d2dffb391e14efb05aa27898f1f6333a9596
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branches/incoming/doc/tutorial.md

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@@ -100,7 +100,7 @@ If you've fulfilled those prerequisites, something along these lines
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should work.
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~~~~ {.notrust}
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$ wget http://dl.rust-lang.org/dist/rust-0.4.tar.gz
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$ curl -O http://dl.rust-lang.org/dist/rust-0.4.tar.gz
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$ tar -xzf rust-0.4.tar.gz
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$ cd rust-0.4
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$ ./configure
@@ -490,7 +490,7 @@ const MY_STRUCTY_PASSWORD: Password = Password { value: MY_PASSWORD };
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## Operators
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Rust's set of operators contains very few surprises. Arithmetic is done with
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`*`, `/`, `%`, `+`, and `-` (multiply, divide, remainder, plus, minus). `-` is
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`*`, `/`, `%`, `+`, and `-` (multiply, divide, take remainder, add, subtract). `-` is
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also a unary prefix operator that negates numbers. As in C, the bit operators
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`>>`, `<<`, `&`, `|`, and `^` are also supported.
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@@ -608,7 +608,7 @@ a wildcard pattern that matches any single value. The asterisk (`*`)
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is a different wildcard that can match one or more fields in an `enum`
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variant.
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The patterns in an match arm are followed by a fat arrow, `=>`, then an
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The patterns in a match arm are followed by a fat arrow, `=>`, then an
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expression to evaluate. Each case is separated by commas. It's often
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convenient to use a block expression for each case, in which case the
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commas are optional.
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}
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~~~~
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You can write a lone `_` to ignore an individual fields, and can
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You can write a lone `_` to ignore an individual field, and can
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ignore all fields of a variant like: `Circle(*)`. As in their
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introduction form, nullary enum patterns are written without
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parentheses.
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Managed boxes are pointers to heap-allocated, garbage collected
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memory. Applying the unary `@` operator to an expression creates a
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managed box. The resulting box contains the result of the
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expression. Copying a shared box, as happens during assignment, only
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expression. Copying a managed box, as happens during assignment, only
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copies a pointer, never the contents of the box.
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~~~~
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In contrast with managed boxes, owned boxes have a single owning
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memory slot and thus two owned boxes may not refer to the same
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memory. All owned boxes across all tasks are allocated on a single
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_exchange heap_, where their uniquely owned nature allows tasks to
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_exchange heap_, where their uniquely-owned nature allows tasks to
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exchange them efficiently.
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Because owned boxes are uniquely owned, copying them requires allocating
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let y = x; // error: copying a non-implicitly copyable type
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~~~~
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If you really want to copy a unique box you must say so explicitly.
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If you really want to copy an owned box you must say so explicitly.
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~~~~
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let x = ~10;
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Rust borrowed pointers are a general purpose reference/pointer type,
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similar to the C++ reference type, but guaranteed to point to valid
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memory. In contrast with owned pointers, where the holder of a unique
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memory. In contrast with owned pointers, where the holder of an owned
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pointer is the owner of the pointed-to memory, borrowed pointers never
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imply ownership. Pointers may be borrowed from any type, in which case
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the pointer is guaranteed not to outlive the value it points to.
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~~~
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# struct Point { x: float, y: float }
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let on_the_stack : Point = Point {x: 3.0, y: 4.0};
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let shared_box : @Point = @Point {x: 5.0, y: 1.0};
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let unique_box : ~Point = ~Point {x: 7.0, y: 9.0};
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let managed_box : @Point = @Point {x: 5.0, y: 1.0};
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let owned_box : ~Point = ~Point {x: 7.0, y: 9.0};
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~~~
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Suppose we wanted to write a procedure that computed the distance
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between any two points, no matter where they were stored. For example,
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we might like to compute the distance between `on_the_stack` and
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`shared_box`, or between `shared_box` and `unique_box`. One option is
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`managed_box`, or between `managed_box` and `owned_box`. One option is
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to define a function that takes two arguments of type point—that is,
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it takes the points by value. But this will cause the points to be
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copied when we call the function. For points, this is probably not so
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~~~
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# struct Point{ x: float, y: float };
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# let on_the_stack : Point = Point {x: 3.0, y: 4.0};
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# let shared_box : @Point = @Point {x: 5.0, y: 1.0};
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# let unique_box : ~Point = ~Point {x: 7.0, y: 9.0};
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# let managed_box : @Point = @Point {x: 5.0, y: 1.0};
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# let owned_box : ~Point = ~Point {x: 7.0, y: 9.0};
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# fn compute_distance(p1: &Point, p2: &Point) -> float { 0f }
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compute_distance(&on_the_stack, shared_box);
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compute_distance(shared_box, unique_box);
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compute_distance(&on_the_stack, managed_box);
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compute_distance(managed_box, owned_box);
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~~~
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Here the `&` operator is used to take the address of the variable
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`on_the_stack`, because we are created an alias: that is, another
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route to the same data.
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In the case of the boxes `shared_box` and `unique_box`, however, no
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In the case of the boxes `managed_box` and `owned_box`, however, no
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explicit action is necessary. The compiler will automatically convert
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a box like `@point` or `~point` to a borrowed pointer like
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`&point`. This is another form of borrowing; in this case, the
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contents of the shared/unique box is being lent out.
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contents of the managed/owned box is being lent out.
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Whenever a value is borrowed, there are some limitations on what you
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can do with the original. For example, if the contents of a variable

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