---

yaml
---
r: 6420
b: refs/heads/master
c: 8e2b5de
h: refs/heads/master
v: v3

Author: marijnh

[refs]

@@ -1,2 +1,2 @@
 ---
-refs/heads/master: 2524636dbde29fef7158f4becd5f957d43ea8a40
+refs/heads/master: 8e2b5de90ea5773db2ce980a252b0038f2eace2e

trunk/doc/tutorial/generic.md

@@ -62,9 +62,9 @@ to assign a type to it. (The same goes for `[]`, in fact.) If you
 really want to have such a statement, you'll have to write it like
 this:
 
-    let n = none::<int>;
+    let n2: option::t<int> = none;
     // or
-    let n2: option::t<int>: none;
+    let n = none::<int>;
 
 Note that, in a value expression, `<` already has a meaning as a
 comparison operator, so you'll have to write `::<T>` to explicitly