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RequirementMachine: Fix silly oversight when resolving concrete types and superclass bounds
The property map stores the concrete type or superclass bound for all
terms whose suffix is equal to some key, so eg if you have
protocol P {
associatedtype T where T == U?
associatedtype U
}
Then you have this rewrite system
[P].T => [P:T]
[P].U => [P:U]
[P:T].[concrete: Optional<τ_0_0> with <[P:U]>] => [P:T]
Which creates this property map
[P:T] => { [concrete: Optional<τ_0_0> with <[P:U]>] }
Now if I start with a generic signature like
<T, U where U : P>
This produces the following rewrite system:
τ_0_1.[U] => τ_0_1
τ_0_1.T => τ_0_1.[P:T]
τ_0_1.U => τ_0_1.[P:U]
Consider the computation of the canonical type of τ_0_1.T. This term
reduces to τ_0_1.[P:T]. The suffix [P:T] has a concrete type symbol in
the property map, [concrete: Optional<τ_0_0> with <[P:U]>].
However it would not be correct to canonicalize τ_0_1.[P:T] to
Optional<τ_0_0>.subst { τ_0_0 => getTypeForTerm([P:T]) }; this
produces the type Optional<τ_0_0.T>, and not Optional<τ_0_1.T> as
expected.
The reason is that the substitution τ_0_0 => getTypeForTerm([P:T])
is "relative" to the protocol Self type of P, since domain([P:T]) = {P}.
Indeed, the right solution here is to note that τ_0_1.[P:T] has a suffix
equal to the key of the property map entry, [P:T]. If we strip off the
suffix, we get τ_0_1. If we then prepend τ_0_1 to the substitution term,
we get the term τ_0_1.[P:U], whose canonical type is τ_0_1.U.
Now, applying the substitution τ_0_0 => τ_0_1.U to Optional<τ_0_0>
produces the desired result, Optional<τ_0_1.U>.
Note that this is the same "prepend a prefix to each substitution of
a concrete type symbol" operation that is performed in checkForOverlap()
and PropertyBag::copyPropertiesFrom(), however we can simplify things
slightly by open-coding it instead of calling the utility method
prependPrefixToConcreteSubstitutions(), since the latter creates a
new symbol, which we don't actually need.
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