[ExpressionLanguage] throw an SyntaxError instead of letting a undefined index notice

Author: Amrouche Hamza

Tests/ExpressionLanguageTest.php

@@ -84,6 +84,15 @@ public function testShortCircuitOperatorsCompile($expression, array $names, $exp
         $this->assertSame($expected, $result);
     }
 
+    /**
+     * @expectedException \Symfony\Component\ExpressionLanguage\SyntaxError
+     * @expectedExceptionMessage Unexpected end of expression around position 6 for expression `node.`.
+     */
+    public function testParseThrowsInsteadOfNotice()
+    {
+        (new ExpressionLanguage())->parse('node.', array('node'));
+    }
+
     public function shortCircuitProviderEvaluate()
     {
         $object = $this->getMockBuilder('stdClass')->setMethods(array('foo'))->getMock();

TokenStream.php

@@ -50,12 +50,12 @@ public function __toString()
      */
     public function next()
     {
+        ++$this->position;
+
         if (!isset($this->tokens[$this->position])) {
             throw new SyntaxError('Unexpected end of expression', $this->current->cursor, $this->expression);
         }
 
-        ++$this->position;
-
         $this->current = $this->tokens[$this->position];
     }