delaySubscription(Func0) does not use a scheduler #3609
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It subscribes to the upstream `Observable` on the emitting thread of the other `Observable` obtained from the `Func0`.
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stealthcode
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Jan 8, 2016
delaySubscription(Func0) does not use a scheduler
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It subscribes to the upstream
Observableon the emitting thread of the otherObservableobtained from theFunc0.