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[SYCL] Default work-group sizes based on max #952

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Mar 25, 2020
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15 changes: 10 additions & 5 deletions sycl/source/detail/scheduler/commands.cpp
Original file line number Diff line number Diff line change
Expand Up @@ -1417,14 +1417,19 @@ static void adjustNDRangePerKernel(NDRDescT &NDR, RT::PiKernel Kernel,

if (WGSize[0] == 0) {
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Is this condition valid to represent all "default work-group size" cases?

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@romanovvlad romanovvlad Mar 2, 2020

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WGSize[0] == 0 means user hasn't asked for a specific local size using attribute((reqd_work_group_size(X, Y, Z)) only.

// kernel does not request specific workgroup shape - set one
// TODO maximum work group size as the local size might not be the best
// choice for CPU or FPGA devices
id<3> MaxWGSizes =
get_device_info<id<3>, cl::sycl::info::device::max_work_item_sizes>::
get(DeviceImpl.getHandleRef(), DeviceImpl.getPlugin());

size_t WGSize1D = get_kernel_work_group_info<
size_t, cl::sycl::info::kernel_work_group::work_group_size>::
get(Kernel, DeviceImpl.getHandleRef(), DeviceImpl.getPlugin());
assert(WGSize1D != 0);
// TODO implement better default for 2D/3D case:
WGSize = {WGSize1D, 1, 1};

assert(MaxWGSizes[2] != 0);

// Set default work-group size in the Z-direction to either the max
// number of work-items or the maximum work-group size in the Z-direction.
WGSize = {1, 1, min(WGSize1D, MaxWGSizes[2])};
}
NDR.set(NDR.Dims, nd_range<3>(NDR.NumWorkGroups * WGSize, WGSize));
}
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