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[3.10] bpo-46820: Fix a SyntaxError in a numeric literal followed by "not in" (GH-31479) #31493

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Feb 22, 2022
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9 changes: 9 additions & 0 deletions Lib/test/test_grammar.py
Original file line number Diff line number Diff line change
Expand Up @@ -251,6 +251,15 @@ def check_error(test):
check("1e3in x")
check("1jin x")

check("0xfnot in x")
check("0o7not in x")
check("0b1not in x")
check("9not in x")
check("0not in x")
check("1.not in x")
check("1e3not in x")
check("1jnot in x")

with warnings.catch_warnings():
warnings.simplefilter('ignore', SyntaxWarning)
check("0xfis x")
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Original file line number Diff line number Diff line change
@@ -0,0 +1,3 @@
Fix parsing a numeric literal immediately (without spaces) followed by "not
in" keywords, like in ``1not in x``. Now the parser only emits a warning,
not a syntax error.
3 changes: 3 additions & 0 deletions Parser/tokenizer.c
Original file line number Diff line number Diff line change
Expand Up @@ -1251,6 +1251,9 @@ verify_end_of_number(struct tok_state *tok, int c, const char *kind)
else if (c == 'o') {
r = lookahead(tok, "r");
}
else if (c == 'n') {
r = lookahead(tok, "ot");
}
if (r) {
tok_backup(tok, c);
if (parser_warn(tok, "invalid %s literal", kind)) {
Expand Down