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bpo-30004: in regex-howto, improve example on grouping #4443

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Nov 25, 2017
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bpo-30004: in regex-howto, improve example on grouping #4443

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b1407d1
Fix regular expressions for finding double words
mandeep Nov 17, 2017
96a4255
Move empty string match expression outside group
mandeep Nov 18, 2017
e489825
Refactor other named group expressions by moving empty string match o…
mandeep Nov 18, 2017
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6 changes: 3 additions & 3 deletions Doc/howto/regex.rst
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Original file line number Diff line number Diff line change
Expand Up @@ -844,7 +844,7 @@ backreferences in a RE.

For example, the following RE detects doubled words in a string. ::

>>> p = re.compile(r'(\b\w+)\s+\1')
>>> p = re.compile(r'\b(\w+)\s+\1\b')
>>> p.search('Paris in the the spring').group()
'the the'

Expand Down Expand Up @@ -943,9 +943,9 @@ number of the group. There's naturally a variant that uses the group name
instead of the number. This is another Python extension: ``(?P=name)`` indicates
that the contents of the group called *name* should again be matched at the
current point. The regular expression for finding doubled words,
``(\b\w+)\s+\1`` can also be written as ``(?P<word>\b\w+)\s+(?P=word)``::
``\b(\w+)\s+\1\b`` can also be written as ``\b(?P<word>\w+)\s+(?P=word)\b``::

>>> p = re.compile(r'(?P<word>\b\w+)\s+(?P=word)')
>>> p = re.compile(r'\b(?P<word>\w+)\s+(?P=word)\b')
>>> p.search('Paris in the the spring').group()
'the the'

Expand Down