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Improve comments from #72617, as suggested by RalfJung #73925
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It is not equivalent. The compiler can optimize relaxed less than it can optimize normal reads.
Another way to see that they are not equivalent: replacing this relaxed access by a normal aligned read would result in Undefined Behavior. If two things are truly equivalent, then replacing one by the other changes nothing.
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What about "In terms of performance, a relaxed atomic load is similar to a normal aligned memory read (e.g., a
mov
instruction in x86), but with some compiler optimization restrictions."?There was a problem hiding this comment.
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That sounds great. :)