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Original file line number Diff line number Diff line change
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# [Sherlock and Anagrams](https://www.hackerrank.com/challenges/sherlock-and-anagrams)

- Difficulty: `#medium`
- Category: `#ProblemSolvingMedium` `#DictionariesAndHashmaps` `#Strings`

Two strings are [http://en.wikipedia.org/wiki/Anagram](anagrams) of each other
if the letters of one string can be rearranged to form the other string.
Given a string, find the number of pairs of substrings of the string that are
anagrams of each other.

## Example

`s = mom`

The list of all anagrammatic pairs is `[m, m]`, `[mo, om]`
at positions `[[0], [2]]`, `[[0, 1], [1, 2]]` respectively.

## Function Description

Complete the function sherlockAndAnagrams in the editor below.

*sherlockAndAnagrams* has the following parameter(s):

- `string s`: a string

## Returns

- `int`: the number of unordered anagrammatic pairs of substrings in **`s`**

## Input Format

The first line contains an integer `q`, the number of queries.
Each of the next `q` lines contains a string `s` to analyze.

## Constraints

- $ 1 \leq 10 \leq 10 $
- $ 2 \leq $ lenght of `s` $ \leq 100 $

`s` contains only lowercase letters in the range ascii[a-z].

## Sample Input 0

```text
2
abba
abcd
```

## Sample Output 0

```text
4
0
```

## Explanation 0

The list of all anagrammatic pairs is `[a, a]`, `[ab, ba]`,
`[b, b]` and `[abb, bba]` at positions `[[0], [3]]`, `[[0, 1]], [[2, 3]]`,
`[[1], [2]]` and `[[0, 1, 2], [1, 2, 3]]` respectively.

No anagrammatic pairs exist in the second query as no character repeats.

## Sample Input 1

```text
2
ifailuhkqq
kkkk
````

## Sample Output 1

```text
3
10
```

## Explanation 1

For the first query, we have anagram pairs `[i, i]`, `[q, q]`
and `[ifa, fai]` at positions `[[0], [3]]`, `[[8], [9]]`
and `[[0, 1, 2], [1, 2, 3]]` respectively.

For the second query:

There are `6` anagrams of the form `[k, k]` at positions `[[0, 1]]`,
`[[0], [2]]`, `[[0], [3]]`, `[[1], [2]]`, `[[1], [3]]` and `[[2], [3]]`.

There are 3 anagrams of the form `[kk, kk]` at positions `[[0, 1], [1, 2]]`,
`[[0, 1], [2, 3]]` and `[[1, 2], [2, 3]]`.

There is 1 anagram of the form `[kkk, kkk]` at position `[[0, 1, 2], [1, 2, 3]]`.

## Sample Input 2

```text
1
cdcd
```

## Sample Output 2

```text
5
```

## Explanation 2

There are two anagrammatic pairs of length `1`: `[c, c]` and `[d, d]`.
There are three anagrammatic pairs of length `2`:
`[cd, dc]`, `[cd, cd]`, `[dc, cd]` at positions
`[[0, 1] [1, 2]]`, `[[0, 1], [2, 3]]`, `[1, 2], [2, 3]` respectively.
Original file line number Diff line number Diff line change
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import { describe, expect, it } from '@jest/globals';
import { logger as console } from '../../../logger';

import { sherlockAndAnagrams } from './sherlock_and_anagrams';

const TEST_CASES = [
{
title: 'Sample Test Case 0',
tests: [
{
input: 'abba',
expected: 4
},
{
input: 'abcd',
expected: 0
}
]
},
{
title: 'Sample Test Case 1',
tests: [
{
input: 'ifailuhkqq',
expected: 3
},
{
input: 'kkkk',
expected: 10
}
]
},
{
title: 'Sample Test Case 1',
tests: [
{
input: 'cdcd',
expected: 5
}
]
}
];

describe('sherlock_and_anagrams', () => {
it('sherlockAndAnagrams test cases', () => {
expect.assertions(5);

TEST_CASES.forEach((testSet) => {
testSet.tests.forEach((test) => {
const answer = sherlockAndAnagrams(test.input);

console.debug(`checkMagazine(${test.input}) solution found: ${answer}`);

expect(answer).toStrictEqual(test.expected);
});
});
});
});
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/**
* @link Problem definition [[docs/hackerrank/interview_preparation_kit/dictionaries_and_hashmaps/sherlock_and_anagrams.md]]
*/

function factorial(n: number): number {
if (n == 0) {
return 1;
}
return n * factorial(n - 1);
}

export function sherlockAndAnagrams(s: string): number {
const candidates: Record<string, string[]> = {};
const size = s.length;

for (let i = 0; i < size; i++) {
for (let j = 0; j < size - i; j++) {
const substr = s.substring(i, size - j);

// Add substrings to a candidate list.
// two strings are anagrams if sorted strings are the same.

const anagram_candidate = substr
.split('')
.sort((a: string, b: string) => a.localeCompare(b))
.join('');
if (anagram_candidate in candidates) {
candidates[anagram_candidate].push(substr);
} else {
candidates[anagram_candidate] = [substr];
}
}
}

let count = 0;
// Final Anagram list
for (const i of Object.keys(candidates)) {
const total = candidates[i].length;
const k = 2;

if (total <= 1) {
delete candidates[i];
} else {
// Binomial coefficient: https://en.wikipedia.org/wiki/Binomial_coefficient
count += Math.floor(
factorial(total) / (factorial(k) * factorial(total - k))
);
}
}
console.debug(`filtered candidates: ${count}`);

return count;
}

export default { sherlockAndAnagrams };