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Fix doc typo on yearForWeekOfYear case in DateComponents #1666

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2 changes: 1 addition & 1 deletion Foundation/DateComponents.swift
Original file line number Diff line number Diff line change
Expand Up @@ -217,7 +217,7 @@ public struct DateComponents : ReferenceConvertible, Hashable, Equatable, _Mutab

/// The ISO 8601 week-numbering year of the receiver.
///
/// The Gregorian calendar defines a week to have 7 days, and a year to have 356 days, or 366 in a leap year. However, neither 356 or 366 divide evenly into a 7 day week, so it is often the case that the last week of a year ends on a day in the next year, and the first week of a year begins in the preceding year. To reconcile this, ISO 8601 defines a week-numbering year, consisting of either 52 or 53 full weeks (364 or 371 days), such that the first week of a year is designated to be the week containing the first Thursday of the year.
/// The Gregorian calendar defines a week to have 7 days, and a year to have 365 days, or 366 in a leap year. However, neither 365 or 366 divide evenly into a 7 day week, so it is often the case that the last week of a year ends on a day in the next year, and the first week of a year begins in the preceding year. To reconcile this, ISO 8601 defines a week-numbering year, consisting of either 52 or 53 full weeks (364 or 371 days), such that the first week of a year is designated to be the week containing the first Thursday of the year.
///
/// You can use the yearForWeekOfYear property with the weekOfYear and weekday properties to get the date corresponding to a particular weekday of a given week of a year. For example, the 6th day of the 53rd week of the year 2005 (ISO 2005-W53-6) corresponds to Sat 1 January 2005 on the Gregorian calendar.
/// - note: This value is interpreted in the context of the calendar in which it is used.
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