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SyntaxNodes: DotSelfExpr should have optional base expression. #21926
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This is a keypath, not a DotSelfExpr. I don't think its correct that DotSelfExpr's base is optional; you should instead parse keypaths differently. CC @jckarter
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We parse them as DotSelfExpr too for AST, see here.
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I see it parses like this:
So the base is a KeyPathDotExpr. Do you not have an equivalent in SwiftSyntax? It would be better if the base was never optional here and with MemberExpr also.
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Syntax tree doesn't have equivalent implicit nodes in general. All nodes should cover at least one underlying token.
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The only exception is collection syntax like
CodeBlockItemList
, which can be an empty set of items.There was a problem hiding this comment.
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a.self
is creating aDotSelfExpr
syntax node while.self
is creating aImplicitMemberExpr
one. If we want to be consistent here then shouldn't\.self
be aKeyPathExpr
wrapping anImplicitMemberExpr
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Also there is a difference in
.a
creating aImplicitMemberExpr
node while\.a
is aMemberAccessExpr
wrapped byKeyPathExpr
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After further discussion with Xi, this is explained by the parser treating these differently,
.self
being aunresolved_member_expr
while\.self
creating adot_self_expr
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Ok, makes sense. Since SwiftSyntax is trying to be more uniform and elegant perhaps it would make sense if
.self
in all contexts was a MemberRefExpr with an identifier ofself
? Does it make sense for it to be its own thing?There was a problem hiding this comment.
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yeah, i think this suggestion makes sense. We could reuse existing
MemberAccessExpr
to coverDotSelfExpr
. We could also useMemberAccessExpr
to representImplicitMemberExpr
to further reduce the type complexity.