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Add default argument for conv2D dilations #286

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Jun 24, 2019
Merged

Add default argument for conv2D dilations #286

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4 changes: 2 additions & 2 deletions Sources/TensorFlow/Operators/NN.swift
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Original file line number Diff line number Diff line change
Expand Up @@ -123,7 +123,7 @@ public func conv2D<Scalar: TensorFlowFloatingPoint>(
filter: Tensor<Scalar>,
strides: (Int, Int, Int, Int),
padding: Padding,
dilations: (Int, Int, Int, Int)
dilations: (Int, Int, Int, Int) = (1, 1, 1, 1)
) -> Tensor<Scalar> {
return Raw.conv2D(
input,
Expand Down Expand Up @@ -200,7 +200,7 @@ func conv2DBackpropFilter<Scalar: TensorFlowFloatingPoint>(
filterSizes: Tensor<Int32>,
strides: (Int, Int, Int, Int),
padding: Padding,
dilations: (Int, Int, Int, Int)
dilations: (Int, Int, Int, Int) = (1, 1, 1, 1)
) -> Tensor<Scalar> {
return Raw.conv2DBackpropFilter(
input,
Expand Down
4 changes: 2 additions & 2 deletions Tests/TensorFlowTests/LayerTests.swift
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Expand Up @@ -20,7 +20,7 @@ final class LayerTests: XCTestCase {
let filter = Tensor<Float>(ones: [3, 1, 2]) * Tensor<Float>([[[0.5, 1]]])
let bias = Tensor<Float>([0, 1])
let layer = Conv1D<Float>(filter: filter, bias: bias, activation: identity, stride: 1,
padding: .valid, dilation: 1)
padding: .valid)
let input = Tensor<Float>([[0, 1, 2, 3, 4], [10, 11, 12, 13, 14]]).expandingShape(at: 2)
let output = layer.inferring(from: input)
let expected = Tensor<Float>(
Expand Down Expand Up @@ -55,7 +55,7 @@ final class LayerTests: XCTestCase {
let filter = Tensor(shape: [1, 2, 2, 1], scalars: (0..<4).map(Float.init))
let bias = Tensor<Float>([1, 2])
let layer = Conv2D<Float>(filter: filter, bias: bias, activation: identity,
strides: (2, 2), padding: .valid, dilations: (1, 1))
strides: (2, 2), padding: .valid)
let input = Tensor(shape: [2, 2, 2, 2], scalars: (0..<16).map(Float.init))
let output = layer.inferring(from: input)
let expected = Tensor<Float>(shape: [2, 1, 1, 2],
Expand Down